Two condensers of capacity `C` and `2C` are connected in parallel and these are charged upto `V` volt. If the battery is removed and dielectric medium of constant `K` is put between the plates of first condenser, then the potential at each condenser is.

A condenser is charged and then battery is removed. A dielectric plate is put between the plates of condenser, then correct statement is

When air is replaced by a dielectric medium of constant K , the capacity of the condenser.

Two capacitors A and B of capacities C and 2C are connected in parallel and the combination is connected to a battery of V volts. After the charging is over , the battery is removed. Now a dielectric slab of K=2 is inserted between the plates of A so as fill the completely. The energy lost by the system during the sharing of charges is (i) With battery of parallel combination :

The parallel combination of two air filled parallel plate capacitor of capacitance C and nC is connected to a battery of voltage, V. When the capacitors are fulley charged, the battery is removed and after that a dielectric material of dielectric constant K is placed between the two plates of the first capacitors. the new potential difference of the combined system is

Putting a dielectric substance between two plates of condenser : capacity, potential and potential energy respectively.

Two condensers, one of capacity C and the other of capacity C//2 , are connected to a V volt battery, as shown The heat produced in connecting wires