A simple pendulum attached to the ceiling of a stationary lift has a time period T. The distance y covered by the lift moving upwards varies with time t as `y = t^(2)` where y is in metres and t in seconds. If `g = 10 m//s^(2)`, the time period of pendulum will be

A simple pendulum attached to the celling of a stationary lift has time period T. The lift starts moving and the position vector of the lift is given as vecr(t)=15t^2hati+15t^2hatj , where r(t) is in meters and t is in seconds. If g=10 m//s^2 , the new time period of oscillation is

A simple pendulum hangs from the ceiling of a stationary. Lift and executes S.H.M. wih a time period T. When the lift started moving upwards, the distance covered by it while moving upwards varies with time t as y = 6t^(2) where y is in metre and t in seconds. Calculate the new time period of the pendulum.

A simple pendulum hanging from the ceiling of a stationary lift has a time period T 1 . When the lift moves downward with constant velocity, the time period is T, then

A simple pendulum attached to ceiling of lift has time period T when lift is at rest. Find its time period of lift it starts accelerating upwards with acceleration g/2?

A simple pendulum suspended from the ceiling of a stationary van, has time period T. If then van stats moving with a uniform velocity, the periodic of the pendulum will be………..

A simple pendulum, suspended from the ceiling of a stationary van, has time period T . If the van starts moving with a uniform velocity the period of the pendulum will be