The electron affinity values (in `kJ mol^(-1))` of three halogens, `x,y`, and `z`are, respectively, `-349, -333`, and `-325`. Then `x, y`, and `x`, are respectively,

Options

A. `F_(2), C1`, and `Br_(2)`
B. `C1_(2),F_(2)`, and `Br_(2)`
C. `C1_(2), Br_(2)`, and `F_(2)`
D. `Br_(2), C1_(2)`, and `F_(2)`

Answer

B

Explanation

The correct order of electron affinity values is
`C1(-349) gt F (-333) gt C1(-325)`