Draw the Lewis structure of iodine pentafluoride, `IF_5`.

Explanation

Step 1: The number of valence electrons is `7+(5xx7)=42`.
Step 2: Since F can form only one bond and only I can form more than one bond (as it is bonded to another halogen of lower atomic number), the skeleton must be

Step 3: The number of electrons remaining to complete octets is `42-10=32`.
Step 4: The number of electrons required to complete the octets of the F atoms is `5xx6=30`. Since I has formed 5 bonds, its valence shell has 10 electrons, i.e., more than octet.
Step 5: Since there are two more electrons than are necessary to complete octets, there is further scope of octet expansion than is found in the given skeleton. The I atom is large enough to accommodate the two extra electrons in its valence shell even though it is already surrounded by 10 electrons.
Completing the Lewis structure by placing dots gives