The formal charges on the three O atoms in the `O_3` molecule are

Options

A. `0,+1,-1`
B. `0,0,+1`
C. `0,0,-1`
D. `0,-1,+1`

Answer

A

Explanation

The Lewis structure of ozone molecule is
`overset(..)underset(..)O=overset(..)O-overset(..)underset(..)O:`
We can calculate the formal charges on the O atoms as follows:
The central O atom: It has six valence electrons in the free state. It has one lone pair (or two nonbonding electrons) and three bonds (or six bonding electrons). Thus,
`FC=(6)-(2)-1/2(6)=+1`
The end O atom in `O=O:` It has six valence electrons in the free state. It has two lone pairs (or four nonbonding electrons) and two bonds(or four bonding electrons). Thus,
`FC=(6)-(4)-1/2(4)=0`
The end O atom in `O-O:` It has six valence electrons, three lone pairs (or six nonbonding electrons), and one bond (or two bonding electrons). Thus,
`FC=(6)-(6)-1/2(2)=-1`