The most polar bond is

Options

A. `O-H`
B. `C-H`
C. `N-H`
D. `F-H`

Explanation

To determine which bond is the most polar among the given options (C-H, N-H, and F-H), we need to analyze the electronegativity values of the involved atoms. Here’s a step-by-step solution:

### Step-by-Step Solution:

1. **Understand Polarity of Bonds**:
- A bond is considered polar when there is a significant difference in electronegativity between the two atoms involved in the bond. The greater the difference, the more polar the bond.

2. **Identify Electronegativity Values**:
- The electronegativity values for the relevant atoms are as follows:
- Fluorine (F): 4.0
- Oxygen (O): 3.44
- Nitrogen (N): 3.04
- Carbon (C): 2.55
- Hydrogen (H): 2.1

3. **Calculate Electronegativity Differences**:
- For each bond, calculate the difference in electronegativity:
- C-H: |2.55 - 2.1| = 0.45
- N-H: |3.04 - 2.1| = 0.94
- F-H: |4.0 - 2.1| = 1.9

4. **Compare the Differences**:
- Now, compare the calculated differences:
- C-H: 0.45
- N-H: 0.94
- F-H: 1.9

5. **Identify the Most Polar Bond**:
- The bond with the largest electronegativity difference is the most polar. From our calculations, the F-H bond has the highest difference of 1.9.

6. **Conclusion**:
- Therefore, the most polar bond among the given options is the **F-H bond**.