In which of the following species the underlined C atom has `sp^3` hybridization?

Options

A. `CH_2=ulCH-CH_3`
B. `CH_3ulCH_2OH`
C. `CH_3ulCOCH_3`
D. `CH_3ulCOOH`

Answer

B

Explanation

`C` atom forming 4 sigma bonds (zero `pi` bonds) is `sp^3`-hybridized, `C` atom forming `3` sigma and `1` pi bonds is `sp^2`-hybridized, and `C` atom forming `2` sigma and `2` pi bonds is `sp`-hybridized.
`{:(CH=underset(sp^(2))overset(H)overset(|)C-CH_(3),,CH_(2)=underset(H)underset(|)overset(H)overset(|)Coverset(sp^(2))-OH),(CH_(3)-underset(sp^(2))overset(O)overset(||)C-CH_(3),,CH_(3)-underset(sp^(2))overset(O)overset(||)C-O-H):}`