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Match the list I and II and choose the correct matching:
`{:(List I(Species),,,,ListII(Geometry)),(A.H_3O^(+),,,,1.Planar),(B.H_2C=NH,,,,2.Angu lar),(C.ClO_2^(-),,,,3.Tetrahedral),(D. NH_4^(+) ,,,,4.Trigonal bipyrami dal),(E.PCl_5,,,,5. Pyrami dal):}`

A

`A-2, B-1, C-3, D-5, E-4`

B

`A-1, B-5, C-2, D-3, E-4`

C

`A-5, B-1, C-2, D-3, E-4`

D

`A-3, B-1, C-4, D-5, E-2`

Text Solution

Verified by Experts

The correct Answer is:
C

`SN` of `O` in `H_3O^(+)` is `3+1=4` (pyramidal), `SN` of `Cl` in `ClO_2^(-)` is `2+2=4`(angular). With these two results, the answer is confirmed (that is the advantage of multiple choice questions). `SN` on `N` in `NH_4^(+)` is `4+0=4` (tetrahedral), `SN` of `P` in `PCl_5` is `5+0=5` (trigonal bipyramidal), `SN` of `C` in `H_2C=NH` is `3+0=3`, and `SN` of `N` in `H_2C=NH` is `2+1=3`. Thus, this molecule is planar.
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