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In [Ag(CN)2]^(-), the number of pi bonds...

In `[Ag(CN)_2]^(-)`, the number of `pi` bonds is

A

`2`

B

`3`

C

`4`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
A
The complete structural formula of `[Ag(CN)_2]^(-)` is `[N-=CrarrAglarrC-=N]^(-)`
Thus, it has `2+2=4pi`(pi) bonds.
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