While `1mol` of ice melts at `0^(@)C` and at constant pressure of `1atm, 1440 cal` of heat are absorbed by the system. The molar volume of ice and water are `0.0196` and `0.0180L` respectively. Calculate `DeltaH` and `DeltaU`.

Explanation

`Delta H = qp = 1440 cal`
According to
`Delta H = Delta U + P Delta V`
Since `P Delta V ~= 0`,
`Delta H ~= Delta H ~= 1440 cal`