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A hypothetical reaction, A rarr 2B, proc...

A hypothetical reaction, `A rarr 2B`, proceeds via following sequence of steps
`{:(ArarrC,,DeltaH = q_(1),,,),(CrarrD,,DeltaH = q_(2),,,),((1)/(2)D rarrB,,DeltaH = q_(3),,,):}`
The heat of reaction is

A

`q_(1) + q_(2) - 2q_(3)`

B

`q_(1) + q_(2) + 2q_(3)`

C

`q_(1) + 2q_(2) - 2q_(3)`

D

`q_(1) - q_(2) + 2q_(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
We want one mole of `A` as reactant, so we write down equation (a) We want two moles of `B` as product, so we multiply equation (c ) by 2. Finally we add the three equation terms-by-term:
`{:(ArarrC,,q_(1)),(CrarrD,,q_(2)),(Drarr2B,,2q_(3)),(bar(Ararr2B),,bar(q_(1)+q_(2)+2q_(3))):}`
Therefore, the heat of hypothetical reaction is `q_(1) + q_(2) + 2q_(3)`.
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