Heavier elements of `p`-block in each group do not form

Options

A. `p_(pi) - p_(pi)` multiple bonds
B. `d_(pi) - p_(pi)` multiple bonds
C. `d_(pi) - d_(pi)` multiple bonds
D. all of these

Answer

A

Explanation

Due to large size of their atoms, `p_(pi) - p_(pi)` multiple bonds are not formed by heavier elements. Remember, pi bonds are weaker (than `sigma` bonds). Thus, if orbitals are large, `p_(pi) - p_(pi)` multiple bonds are not formed.