Which of the following compounds contains more than one kind of hybridized carbons?

Options

A. (1) `CH_(3)CH_(2)CH_(2)CH_(3)`
B. (2) `CH_(3)CH=CHCH_(3)`
C. (3) `CH_(2)=CH-CH_(2)`
D. (4) `CH_(2)-=CH`

Answer

B

Explanation

`sp^(3) C` forms `4 sigma` bonds, `sp^(2) C` forms `3 sigma` bonds and `1 pi` bond and `sp C` atom forms `2 sigma` bonds and `2 pi` bonds :
`overset(sp^(3))(CH_(3))overset(sp^(2))(CH_(2))overset(sp^(2))(CH_(2))overset(sp^(3))(CH_(3))` , `overset(sp^(3))(CH_(3))overset(sp^(2))(CH)=overset(sp^(2))(CH)overset(sp^(3))(CH_(3))`
`overset(sp^(2))(CH_(2))overset(sp^(2))(CH)=overset(sp^(2))(CH)overset(sp^(2))(CH_(2))` , `overset(sp)(CH)-=overset(sp)(CH)`