In the straight-chain hydrocarbon `C_(8)H_(10)`, the `C` atoms beginning from one end have the hybridizations `sp^(3), sp^(2), sp^(2),sp^(3), sp^(2),sp^(2),sp`, and `sp`, respectively. The hydrocarbon is

Options

A. (1) `CH_(3)C-=C CH_(2)CH=CHCH=CH_(2)`
B. (2) `CH_(3)CH_(2)CH=CHCH_(2)C-=C CH=CH_(2)`
C. (3) `CH_(3)CH=CHCH_(2)C-=C CH=CH_(2)`
D. (4) `CH_(3)CH=CHCH_(2)CH-=CHC=CH`

Explanation

`overset(sp^(3))(CH_(3))overset(sp^(2))(CH)=overset(sp^(2))
(CH)overset(sp^(3))(CH_(2))overset(sp^(2))(CH)overset(sp^(3))(CH_(2))=overset(sp^(2))(CH)overset(sp)(C)-=overset(sp)(CH)`
According to the given hybridization scheme the molecule should end with a triple bond.