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In the Carius method of estimation of ha...

In the Carius method of estimation of halogen, `0.0811 g` of an organic compound gave `0.2368 g` of `AgCl`. Find the percentage of chlorive in the compound.
Strategy: Find the molar mass of `AgCl` to calculate the moles of `AgCl` which is also equal to the moles of `Cl`, according to the formula. Using molar mass of `Cl`, find its mass to calculate its percentage.

Text Solution

Verified by Experts

Molar mass of `AgCl = (108 + 35.5)g`
`= 143.5 g`
`n_(AgCl) = ("Mass of" AgCl)/("Molar mass of" AgCl) = (0.2368 g)/(143.5 g mol^(-1))`
`n_(Cl) = n_(AgCl) = (0.2368 g)/(143.5 g mol^(-1))`
`m_(Cl) = n_(Cl) xx" Molar mass"_(Cl)`
`= (0.2368 g)/(143.5 g mol^(-1)) xx 35.5 g mol^(-1)`
`%` of `Cl` in organic compound `= (m_(Cl))/(m_(o .c.)) xx 100%`
`= (0.2368 xx 35.5)/(143.5 xx 0.0811) xx 100%`
`= 72.24 %`
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Knowledge Check

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