In the Carius method of estimation of sulphur, `0.36 g` of an organic compound gave `0.2330 g BaSO_(4)`. What is the percentage of sulphur in the organic compound?
Strategy: Using the atomic masses, find the molar mass of `BaSO_(4)`. Calculate the moles of `BaSO_(4)` which is also equal to the moles of `S`. Using molar mass of `S`, find the mass of `S` to calculate the `%` of `S` in the organic compound.

Explanation

Molar mass of `BaSO_(4) = (137 + 32 + 4 xx 16) g = 233 g`
`n_(BaSO_(4)) = (Mass_(BaSO_(4)))/("molar mass"_(BaSO_(4))) = (0.2330 g)/(233 g mol^(-1)) = n_(s)`
`m_(s) = n_(s) xx "Molar mass"_(s) = (0.2330)/(233) mol xx 32 g mol^(-1)`
`%` of `S` in organic compound
`= (m_(s))/(m_(o c.)) xx 100% = (0.2330 xx 32)/(233 xx 0.36) xx 100%`
`= 8.89 %`