`0.0833 `mol of carbohydrate of empirical formula `CH_(2)O` contain `1 g ` of hydrogen. The molecular formula of the carbohydrate is

Options

A. `C_(6)H_(12)O_(6)`
B. `C_(5)H_(10)O_(5)`
C. `C_(3)H_(4)O_(3)`
D. `C_(6)H_(12)O_(5)`

Answer

A

Explanation

`0.833 mol` of carbihydrate contains `10 g` hydrogen. Thus, `1 mol` of the compound will certain
`(10 g)/(0.833 mol) = 12 g mol^(-1)`
This implies that `1` molecule of carbohydrate contains `12 u` of `H (or (12 u)/(1 u "atom"^(-1)) = 12 at oms of H)`
`:.` Molecular formula `= C_(6)H_(12)O_(6)`