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The empirical formula of a compound is C...

The empirical formula of a compound is `CH_(2)`. IF one mole of the compound has a mass of `42 g`, its molecular formula is

A

`CH_(2)`

B

`C_(3)H_(6)`

C

`C_(2)H_(2)`

D

`C_(3)H_(8)`

Text Solution

Verified by Experts

The correct Answer is:
B

Molecular formula `= n` (Empirical formula)
`n = ("Molecular mass")/("Empirical formula mass") = (42 u)/(14 u) = 3`
`:. M.F. = 3(CH_(2)O) = C_(3)H_(6)O_(3)`
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