Percentage of `Se` (atomic mass `= 78.4 u`) in peroxidase anhydrase enzyme is `0.5%` by mass. The minimum molecular mass of peroxidase anhydrase enzyme is

Options

A. `136xx10^(4)`
B. `568xx10^(3)`
C. `15.28`
D. `568 xx 10^(4)`

Answer

D

Explanation

Since minimum molecular mass of enzyme corresponds to minimum number of Se atoms, i.e., just one atom of Se, we have
`%` of `Se = ((At.mass)_(se))/(("Min.mol.mass")_("Enzyme")) xx 100%`
Thus, minimum molecular mass of enzyme
`=((At.mass)_(se))/(%Se) xx 100%`
`=(78.4u)/(0.5%) xx 100%`
`= 15680 u = 1567 xx 10^(4)`