During Lassaigne's test , `N` and `S` present in an organic compound change into

Options

A. `Na_(2)S` and `NaCN`
B. `NaSCN`
C. `Na_(2)SO_(4)` and `NaCN`
D. `Na_(2)S + NaCNO`

Explanation

**Step-by-Step Solution:**

1. **Understanding Lassaigne's Test:**
Lassaigne's test is a qualitative analysis method used to detect the presence of nitrogen (N) and sulfur (S) in organic compounds. The organic compound is fused with sodium metal (Na) to form sodium salts of the elements present in the compound.

2. **Fusion Process:**
When the organic compound containing nitrogen and sulfur is fused with sodium, the nitrogen and sulfur are converted into sodium compounds. The general reaction can be represented as:
\[ \text{Organic Compound} + \text{Na} \rightarrow \text{NaCN (if N is present)} + \text{Na2S (if S is present)} \]

3. **Formation of Sodium Compounds:**
- **Nitrogen:** If nitrogen is present, it forms sodium cyanide (NaCN).
- **Sulfur:** If sulfur is present, it forms sodium sulfide (Na2S).

4. **Final Products:**
If both nitrogen and sulfur are present, the products formed will be sodium thiocyanate (NaCNS) as a result of the reaction between sodium cyanide and sodium sulfide:
\[ \text{NaCN} + \text{Na2S} \rightarrow \text{NaCNS} \]

5. **Conclusion:**
Therefore, during Lassaigne's test, nitrogen (N) and sulfur (S) present in an organic compound change into sodium thiocyanate (NaCNS) when both are present.

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