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Which of the following compounds prosses...

Which of the following compounds prossesses the `C-H` bonds with the lowest bond dissociation energy?

A

Toluene

B

Benzene

C

`n`-Pentane

D

`2,2`-Dimethylpropane

Text Solution

Verified by Experts

The correct Answer is:
A
When we break the `C-H` bond homolytically, free radical carrying odd `e^(-)` on the `C` atom are formed. The more stable are radical, the lesser is the bond dissociation energy.


Due to resonance, benzyl free radical is the most stable of all these free radicals. Thus, toluene has the lowest `C-H` bond dissociation enthalpy.
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