The number of possible structural isomers of `C_4H_(10)O` is

Options

A. 7
B. 8
C. 6
D. 5

Explanation

To determine the number of possible structural isomers of the compound with the formula \( C_4H_{10}O \), we can follow these steps:

### Step 1: Identify the Types of Isomers
The compound \( C_4H_{10}O \) can have two types of structural isomers:
1. Monohydric alcohols
2. Ethers

### Step 2: Count Monohydric Alcohol Isomers
We will first identify the possible monohydric alcohols. Monohydric alcohols have the functional group -OH (hydroxyl group).

1. **Butan-1-ol**: \( CH_3-CH_2-CH_2-CH_2OH \)
2. **Butan-2-ol**: \( CH_3-CH(OH)-CH_2-CH_3 \)
3. **Isobutanol (2-methylpropan-1-ol)**: \( (CH_3)_2CH-CH_2OH \)
4. **Tert-butanol (2-methylpropan-2-ol)**: \( (CH_3)_3C-OH \)

Thus, we have **4 structural isomers of monohydric alcohols**.

### Step 3: Count Ether Isomers
Next, we will identify the possible ethers. Ethers have the general structure \( R-O-R' \).

1. **Dimethyl ether**: \( CH_3-O-CH_3 \)
2. **Ethyl methyl ether**: \( CH_3-CH_2-O-CH_3 \)
3. **Butyl methyl ether**: \( CH_3-CH_2-CH_2-O-CH_3 \)
4. **Isobutyl methyl ether**: \( (CH_3)_2CH-CH_2-O-CH_3 \)
5. **Butyl ethyl ether**: \( CH_3-CH_2-CH_2-O-CH_2-CH_3 \)

Thus, we have **5 structural isomers of ethers**.

### Step 4: Total Isomers
Now, we can add the number of structural isomers from both categories:
- Monohydric alcohols: 4
- Ethers: 5

Total structural isomers = 4 (alcohols) + 5 (ethers) = **9 structural isomers**.

### Final Answer
The number of possible structural isomers of \( C_4H_{10}O \) is **9**.

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