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Among the following, the aromatic compou...

Among the following, the aromatic compound is

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B

C

D

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To determine which of the given compounds is aromatic, we will apply Huckel's rule, which states that a compound must satisfy three criteria to be classified as aromatic: 1. The structure must be planar. 2. There must be delocalization of π electrons. 3. The compound must have \(4n + 2\) π electrons, where \(n\) is a non-negative integer. Now, let's analyze each compound step by step. ### Step 1: Analyze the First Compound (Cyclopropene) - **Structure**: Cyclopropene is a three-membered ring with a double bond. - **Planarity**: The structure is planar. - **Delocalization**: There is delocalization of π electrons due to the double bond. - **Count π Electrons**: Cyclopropene has 2 π electrons (from the double bond). - **Check Huckel's Rule**: For \(n = 0\), \(4n + 2 = 2\). This condition is satisfied. **Conclusion**: Cyclopropene is aromatic. ### Step 2: Analyze the Second Compound (Cyclopentene) - **Structure**: Cyclopentene is a five-membered ring with one double bond. - **Planarity**: The structure is planar. - **Delocalization**: There is delocalization of π electrons. - **Count π Electrons**: Cyclopentene has 4 π electrons (2 from the double bond and 2 from the carbocation). - **Check Huckel's Rule**: For \(n = 1\), \(4n + 2 = 6\). For \(n = 0\), \(4n + 2 = 2\). This condition is not satisfied as it has 4 π electrons. **Conclusion**: Cyclopentene is anti-aromatic. ### Step 3: Analyze the Third Compound (Cyclobutene) - **Structure**: Cyclobutene is a four-membered ring with one double bond. - **Planarity**: The structure is planar. - **Delocalization**: There is delocalization of π electrons. - **Count π Electrons**: Cyclobutene has 4 π electrons (2 from the double bond). - **Check Huckel's Rule**: For \(n = 1\), \(4n + 2 = 6\). For \(n = 0\), \(4n + 2 = 2\). This condition is not satisfied as it has 4 π electrons. **Conclusion**: Cyclobutene is anti-aromatic. ### Step 4: Analyze the Fourth Compound (Cyclopropene with a Lone Pair) - **Structure**: This compound has a lone pair and is a three-membered ring. - **Planarity**: The structure is planar. - **Delocalization**: There is delocalization of π electrons. - **Count π Electrons**: This compound has 4 π electrons (2 from the double bonds and 2 from the lone pair). - **Check Huckel's Rule**: For \(n = 1\), \(4n + 2 = 6\). For \(n = 0\), \(4n + 2 = 2\). This condition is not satisfied as it has 4 π electrons. **Conclusion**: This compound is also anti-aromatic. ### Final Conclusion Among the given compounds, the only aromatic compound is **Cyclopropene**. ---

To determine which of the given compounds is aromatic, we will apply Huckel's rule, which states that a compound must satisfy three criteria to be classified as aromatic: 1. The structure must be planar. 2. There must be delocalization of π electrons. 3. The compound must have \(4n + 2\) π electrons, where \(n\) is a non-negative integer. Now, let's analyze each compound step by step. ...
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