In the solvay process.

Options

A. Brine solution is carbonated with `CO_(2)` to from `NaHCO_(3)` which on decomposition at `150^(@)C` produces `Na_(2)CO_(3)`
B. Sodium amalgam reacts with water to produce NaOH, Which on treatment with `CO_(2)` gives `Na_(2)CO_(3)`
C. Carbon dioxide is passed through ammoniacal brine to form `NaHCO_(3)` which on decomposition at `150^(@)C` produces `Na_(2)CO_(3)`
D. brine solution is made to react with `BaCO_(3)` to produce `Na_(2)CO_(3)`

Answer

C

Explanation

The process is based o the principle that when `CO_(2)(g)` is passed through brine (sodium chloride) solution saturated with ammonia, the following ions are present in the solution.
`Na^(+),NH_(4)^(+),Cl^(-), and HCO_(3)^(-)`
Out of the various compound possible, sodium bicarbonate being sparingly soluble soluble precipitates out. this is finally calcined to form sodium carbonates.