An known alkene with formula `C_(7)H_(12)` on oxidation with hot alkaline `KMnO_(4)` yields only the following product
`CH_(3)-overset(O)overset(||)C-CH_(2)CH_(2)CH_(2)CH_(2)-overset(O)overset(||)C-OH`
What is the structure of this alkene?
Strategy:
`C_(7)H_(12)underset((2)H_(3)O^(+))overset((1)KMnO_(4),H_(2)O,Ooverset(-)H)rarrCH_(3)overset(O)overset(||)C CH_(2)CH_(2)CH_(2)CH_(2)overset(O)overset(||)C-OH`
Since the oxidation cleavage leads to just one product which contains the same number of carbon atoms as the reactant, the unknown alkene must have a double bond contained in a ring. The oxidative cleavage of the double bond result in the opening of the ring. To create the ring, remove the -`OH` group and doubly bonded `O's` and finally join the carboxylic acid carbon with ketone carbon by a double bond.

Explanation