In dehydrohalgenation by ethanolic KOH, ...

In dehydrohalgenation by ethanolic `KOH`, the active base is

A

ethanol

B

`KOH`

C

ethoxide ion

D

hydroxide ion

Text Solution

Verified by Experts

The correct Answer is:

C

`OH^(-)+C_(2)H_(5)OHoverset(rarr)larrC_(2)H_(5)O^(-)+H_(2)O`
Ethoxide ion is a stronger base tan hydroxide ion.

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