Prop-`1`-ol can be prepared from propene

Options

A. `H_(2)`/`H_(2)SO_(4)`
B. `Hg(OAC)_(2)//H_(2)O` followed by `NaBH_(4)`
C. `B_(2)H_(6)` followed by `H_(2)O_(2)`
D. `CH_(3)COOH//H_(2)SO_(4)`

Answer

C

Explanation

Reagents `(1)` and `(2)` will lead to the formation of propan-`2`-ol. Reagent `(3)` performs hydroboration-oxidation which leads to the formation of anti-Markovnikov's alcohol:
`CH_(3)CH=CH_(2)overset(B_(2)H_(6))rarr(CH_(3)CH_(2)CH_(2))_(3)Boverset(H_(2)O_(2))rarrCH_(3)CH_(2)CH_(2)OH`