Ozonolysis of `C_(7)H_(14)` gace `2`-methylpentan-`3`-one. The alkene is

Options

A. `2`-ethyl-`3`-methylbut-`1`-ene
B. `3`-ethyl-`2`-methylbut-`3`-ene
C. `2,5`-dimethyl-`3,4`-dimethylhex-`3`-ene
D. `3`-ethyl-`2`-methylbut-`1`-ene

Answer

A

Explanation

The given ketone has the structure
`CH_(3)-overset(CH_(3))overset(|)C-overset(O)overset(||)C-CH_(2)CH_(3)`
It has `6` carbon atoms, Since the alkene `(C_(7)H_(14))` has `7` carbon atoms, it indicates that the alkene under consideration is a terminal alkene `(RCH=CH_(2))`. Thus, along with the given ketone, the other product is formaldehyde `(CH_(2)=O)`: