Buta-`1,3`-diene when treated with `Br_(2)` gives

Options

A. `1,4`-dibromobut-`2`-ene
B. `1,3`-dibromobut-`2`-ene
C. `3,4`-dibromobut-`1`-ene
D. `2,3`-dibromobut-`2`-ene

Explanation

To solve the question about the reaction of Buta-1,3-diene with Br₂, we will follow these steps:

### Step 1: Identify the structure of Buta-1,3-diene
Buta-1,3-diene has the following structure:
\[ \text{CH}_2=CH-CH=CH_2 \]
This means it has two double bonds located between the first and second carbon, and between the third and fourth carbon.

### Step 2: Understand the reaction with Br₂
When Buta-1,3-diene reacts with bromine (Br₂), the bromine molecule acts as an electrophile. The double bonds in Buta-1,3-diene can react with bromine to form a dibrominated product.

### Step 3: Mechanism of the reaction
1. **Electrophilic attack**: The Br₂ molecule approaches the double bond. One of the bromine atoms will attack one of the double bonds, leading to the formation of a cyclic bromonium ion intermediate.
2. **Carbocation formation**: The attack of Br will create a carbocation at the adjacent carbon atom. The stability of this carbocation will influence the reaction pathway.
3. **Nucleophilic attack**: The other bromine atom will then attack the carbocation, leading to the addition of bromine across the double bond.

### Step 4: Determine the product
The product formed from the addition of Br₂ to Buta-1,3-diene will be 1,4-dibromobutane. The structure of the product can be represented as:
\[ \text{CH}_2Br-CH=CH-CH_2Br \]

### Step 5: Final product
The final product of the reaction of Buta-1,3-diene with Br₂ is 1,4-dibromobutane.

### Summary of the reaction:
The reaction of Buta-1,3-diene with bromine results in the formation of 1,4-dibromobutane.

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