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In the reaction M and R...

In the reaction

`M and R`

A

`CH_(3)CH_(2)Cl and NaOH`

B

`CH_(2)ClCH_(2)OH` and aq. `NaHCO_(3)`

C

`CH_(3)CH_(2)OH` and `HCl`

D

Text Solution

Verified by Experts

The correct Answer is:
B
`CH_(2)=CH_(2)+HOClrarrunderset((M))(ClCH_(2)OH)overset(aq.NaHCO_(3)(R ))underset(Delta)rarrHOCH_(2)CH_(2)OH+NaCl+CO_(2)`
Thus, by passing ethylene into hypochlorous acid and then hydrolyzing ethylene chlorohydrin by boiling with aqueous sodium hydrogen carbonate, we can prepare ethylene glycol.
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