Two loops P and Q are made from a uniform wire. The redii of P and Q are `r_(1)and r_(2)` respectively, and their moments of inertia are `I_(1)and I_(2)` respectively, If`I_(2)=4I_(1),"then" r_(2)/r_(1)"equals"`-

Two loops P and Q are made from a uniform wire. The radii of P and Q are r_1 and r_2 respectively and their moments of inertia are I_1 and I_2 respectively. If I_1//I_2 = 4 , then r_2//r_1 equals

Two loops P and Q are made from a uniform wire. The radii of P and Q are R_(1) and R_(2) respectively and their moments of inertia are I_(P) and I_(Q) respectively. If (I_(P))/(I_(Q))=8 then (R_(1))/(R_(2)) is

Two loops P and Q are made from a uniform wire. The radii of P and Q are R_(1) and R_(2) , respectively, and their moments of inertia about their axis of rotation are I_(1) and I_(2) , respectively. If (I_(1))/(I_(2))=4 , then (R_(2))/(R_(1)) is

Two loops P and Q are made from a uniform wire. The radii of P and Q are R_(1) and R_(2) , respectively, and their moments of inertia about their axis of rotation are I_(1) and I_(2) , respectively. If (I_(1))/(I_(2))=4 , then (R_(2))/(R_(1)) is

Thicknesses of two iron discs of radii r and 4r are t and (t)/(4) respectively. If their moments of inertia are I_(1) and I_(2) respectively then

X and Y are two loops made from same wire. The radii of X and Y are r_(1) and r_(2) and their M.I are I_(1) and I_(2) . If I_(2)//I_(1)=4 the value of r_(2)/r_(1) is (K)^(1//3) . Find the value of K.

In the given circuit if I_(1) and I_(2) be the current in resistance R_(1) and R_(2) respectively then:

Two solid spheres A and B each of radius R are made of materials of densities P_(A) and P_(B) respectively. Their moments of inertia about a diameter are I_(A) and I_(B) respectively. The value of I_(A)//I_(B) is