A particle has initial velocity `(2 vec(i)+3 vec(j))` and acceleration `(0.3 vec (i)+0.2 vec (j))`. The magnitude of velocity after 10 seconds will be

A particle has an initial velocity 2 \hat { \i } + 3 \hat { \j } and acceleration 0.3 \hat { \i } + 0.2 \hat { \j } . The magnitude of velocity after 10 seconds will be:

2vec i*3vec j

A particle has initial velocity vec(v)=3hat(i)+4hat(j) and a constant force vec(F)=4hat(i)-3hat(j) acts on the particle. The path of the particle is :

A unit vector perpendicular to 2vec(i) + 3vec(j) + 4vec(k) and 3vec(j) + 2vec(k) is

Find the angle between the vectors vec(i) + 2vec(j) + 3vec(k) and 3vec(i) - vec(j) + 2vec(k) .

If alpha=2vec(i) +3vec(j) -5vec(k) and beta= vec(i)-vec(j) , then find the value of alpha . beta

If vec(b) = 3 vec(i) + 4 vec(j) and vec(a) = hat(i) - vec(j) the vector having the same magnitude as that of vec(b) and parallel to vec(a) is

If the velocity is vec(v) = 2 hat(i) + t^(2) hat(j) - 9 vec(k) , then the magnitude of acceleration at t = 0 . 5 s is :

The position of the particle is given by vec(r )=(vec(i)+2vec(j)-vec(k)) momentum vec(P)= (3vec(i)+4vec(j)-2vec(k)) . The angular momentum is perpendicular to