Home
Class 12
CHEMISTRY
If the radius of the octahedral void is ...

If the radius of the octahedral void is `r` and radius of the atom in closet packed structure is `R` then

A

`r//R=0.414`

B

`r//R=0.225`

C

`r//R=0.155`

D

`r//R=0.732`

Text Solution

AI Generated Solution

The correct Answer is:
To find the relationship between the radius of the octahedral void (r) and the radius of the atom in the closest packed structure (R), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Structure**: In a close-packed structure (like face-centered cubic or body-centered cubic), atoms are arranged in a way that maximizes packing efficiency. The octahedral void is a space between atoms where another atom can fit. 2. **Visualizing the Atoms and Voids**: In a close-packed arrangement, consider two atoms touching each other. The distance between their centers is 2R (where R is the radius of the atom). 3. **Identifying the Geometry**: The octahedral void is formed by the arrangement of four atoms at the corners of a square and one atom at the center. The distance from the center of the octahedral void to the corner atoms is r (the radius of the void). 4. **Using Right Triangle Properties**: If we consider the triangle formed by the centers of the atoms and the center of the octahedral void, we can denote the points as A, B, and C: - Let A and B be the centers of two adjacent atoms. - Let C be the center of the octahedral void. 5. **Setting Up the Right Triangle**: In triangle ABC: - AB = 2R (distance between the two atoms) - AC = r (distance from the center of the void to the center of one atom) - BC = r (distance from the center of the void to the center of the other atom) 6. **Applying the Pythagorean Theorem**: Since triangle ABC is a right triangle, we can apply the Pythagorean theorem: \[ AC^2 + BC^2 = AB^2 \] Substituting the values: \[ r^2 + r^2 = (2R)^2 \] This simplifies to: \[ 2r^2 = 4R^2 \] 7. **Solving for r in terms of R**: Dividing both sides by 2: \[ r^2 = 2R^2 \] Taking the square root of both sides gives: \[ r = R\sqrt{2} \] ### Final Relationship: Thus, the relationship between the radius of the octahedral void (r) and the radius of the atom (R) in a closest packed structure is: \[ r = R\sqrt{2} \]

To find the relationship between the radius of the octahedral void (r) and the radius of the atom in the closest packed structure (R), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Structure**: In a close-packed structure (like face-centered cubic or body-centered cubic), atoms are arranged in a way that maximizes packing efficiency. The octahedral void is a space between atoms where another atom can fit. 2. **Visualizing the Atoms and Voids**: In a close-packed arrangement, consider two atoms touching each other. The distance between their centers is 2R (where R is the radius of the atom). ...
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

(a) If the radius of octahedral void is 'r' and the radius of the atoms in close packing is 'R' what is the relation between 'r' and 'R' ? (b) A metal crystallises in body centred cubic structure. If 'a' is the edge length of its unit cell, 'r' is the radius of the sphere, what is the relation between 'r' and 'a' ?

If r is the radius of the octahedral voids and R is the radius of the atom in close packing,then :

If the radius of the octaheral void is r and the radius of the atoms in close-packing is R , derive relation between r and R

(a) If the radius of octahedral void is r and the radius of the atoms in the close packing is R, derive a relationship between r and R. (b) What is a semiconductor? Describe the two main types of semiconductors and conductor and contrast conduction mechanism in them.

If R is the radius of the octahedral voids and r is the radius of the atom in close packing, then r//R is equal to

If radius of an octahedral void is r and atomic radius of atoms assuming cubical close pacting is R. Then the relation between r and R is

R SHARMA-SOLID STATE-QUESTION BANK level 2
  1. Coordinating number of Na^(+) in NaCl is

    Text Solution

    |

  2. Which of the following is correct for closest packed structure?

    Text Solution

    |

  3. If the radius of the octahedral void is r and radius of the atom in cl...

    Text Solution

    |

  4. Which of the following elements exhibits ferromagetism?

    Text Solution

    |

  5. The edge length of face centred cubic unit cell is 5.8 pm. if the radi...

    Text Solution

    |

  6. Schottky defect in a crystal is observed when

    Text Solution

    |

  7. The intermetallic compounds LiAg crystallises in cubic lattice in whic...

    Text Solution

    |

  8. When electrons are trapped into the crystalline anion vacancy the def...

    Text Solution

    |

  9. In the fluorite structure the coordination number of Ca^(2+) ion is

    Text Solution

    |

  10. For orthorhombic system axial ratios are a nebnec and the axial angle ...

    Text Solution

    |

  11. Most crystals show good cleavage because their atoms ions or molecules...

    Text Solution

    |

  12. Three element A,B,C crystallize into a cubic solid lattice.Atoms A occ...

    Text Solution

    |

  13. Schottky defect occurs mainly in electrovalent compounds where

    Text Solution

    |

  14. Which of the following shows ferrimagnetism?

    Text Solution

    |

  15. If Z is the number of atoms in the unit cell that represent the closed...

    Text Solution

    |

  16. A metal crystallises in a bcc lattice ,its unit cell edge length in ab...

    Text Solution

    |

  17. In face -centered cubic unit cell, edge length is

    Text Solution

    |

  18. On doping Ge with a little of In or Ga one gets

    Text Solution

    |

  19. A compound is formed by elements A and B. This crystallises in the cub...

    Text Solution

    |

  20. A semiconductor of Ge can be made p-type by adding

    Text Solution

    |