For the cell reaction
`Cu^(2+)(C_(1),aq.)+Zn(s)hArrZn^(2+)(C_(2),aq)+Cu(s)`
of an electrochemical cell, the change in free energy `(DeltaG)` of a given temperature is a funcation of

Options

A. In `C_(1)`
B. In `C_(2)`
C. In`(C_(1) + C_(2))`
D. In`(C_(2)//C_(1))`

Answer

D

Explanation

We are given
`Cu^(2+)(C_(1),aq.)+Zn(s)hArrZn^(2+)(C_(2).aq.)+Cu(s)`
According to Nernst equation
`E_("cell") = E_("cell")^(@)-(2.303 RT)/(2F)"log" (C_(Zn^(2+)))/(C_(Cu^(2+)))`
`E_("cell")^(@)-(2.303 RT)/(2F)"log"(C_(2))/(C_(1))`
Thus, `E_("cell")` (at a given temperature) is a funcation of `log C_(2)//C_(1)`.
Since
`DeltaG_("cell") = -nfE_("cell")`
We conclude that, `Delta_("cell")` (at a given temperature) is also a funcation of `log C_(2)//C_(1)`.