The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)

Options

A. `6 xx 10^(23)`
B. `6 xx 10^(20)`
C. `3.75 xx 10^(20)`
D. `7.48 xx 10^(23)`

Explanation

To solve the problem of determining the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds, we will follow these steps:

### Step 1: Calculate the total charge (Q) delivered
The total charge delivered can be calculated using the formula:
\[ Q = I \times t \]
where:
- \( I \) is the current in amperes (A)
- \( t \) is the time in seconds (s)

Given:
- \( I = 1 \, \text{A} \)
- \( t = 60 \, \text{s} \)

Substituting the values:
\[ Q = 1 \, \text{A} \times 60 \, \text{s} = 60 \, \text{C} \]

### Step 2: Calculate the number of electrons (N)
The number of electrons can be calculated using the formula:
\[ N = \frac{Q}{e} \]
where:
- \( N \) is the number of electrons
- \( Q \) is the total charge (calculated in Step 1)
- \( e \) is the charge of one electron, which is given as \( 1.60 \times 10^{-19} \, \text{C} \)

Substituting the values:
\[ N = \frac{60 \, \text{C}}{1.60 \times 10^{-19} \, \text{C}} \]

### Step 3: Perform the calculation
Calculating the value:
\[ N = \frac{60}{1.60 \times 10^{-19}} \]

Calculating this gives:
\[ N = 37.5 \times 10^{19} \]

### Step 4: Express in standard form
To express this in standard scientific notation:
\[ N = 3.75 \times 10^{20} \]

### Final Answer
Thus, the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is:
\[ \boxed{3.75 \times 10^{20}} \]

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