The weight of silver (at `wt. = 108`) displaced by a quantity of electricity which displaced `5600 mL` of `O_(2)` at `STP` will be:

Options

A. `5.4 g`
B. `10.8 g`
C. `54.0 g`
D. `108.0 g`

Explanation

To solve the problem of finding the weight of silver displaced by a quantity of electricity that displaced 5600 mL of O₂ at STP, we can follow these steps:

### Step-by-Step Solution:

1. **Convert Volume of O₂ to Moles:**
- At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L or 22400 mL.
- Given volume of O₂ = 5600 mL.
- To find the number of moles of O₂:
\[ \text{Number of moles of } O_2 = \frac{\text{Volume of } O_2}{\text{Molar volume at STP}} = \frac{5600 \text{ mL}}{22400 \text{ mL/mol}} = \frac{1}{4} \text{ moles} \]

2. **Calculate the Weight of O₂:**
- The molecular weight of O₂ = 32 g/mol.
- Therefore, the weight of O₂ displaced is:
\[ \text{Weight of } O_2 = \text{Number of moles} \times \text{Molecular weight} = \frac{1}{4} \text{ moles} \times 32 \text{ g/mol} = 8 \text{ g} \]

3. **Determine the Equivalent Weight of O₂:**
- The equivalent weight of O₂ (for the reaction producing O₂) is equal to its molecular weight divided by the number of electrons transferred. In the electrolysis of water, 1 mole of O₂ corresponds to the transfer of 4 moles of electrons.
- Therefore, the equivalent weight of O₂ is:
\[ \text{Equivalent weight of } O_2 = \frac{32 \text{ g}}{4} = 8 \text{ g/equiv} \]

4. **Set Up the Relationship for Silver (Ag):**
- According to Faraday's laws of electrolysis, the weight of silver (Ag) displaced is proportional to the weight of O₂ displaced:
\[ \frac{\text{Weight of } Ag}{\text{Equivalent weight of } Ag} = \frac{\text{Weight of } O_2}{\text{Equivalent weight of } O_2} \]
- The equivalent weight of silver (Ag) can be calculated as:
\[ \text{Equivalent weight of } Ag = \frac{\text{Atomic weight of } Ag}{1} = 108 \text{ g/equiv} \]

5. **Calculate the Weight of Silver:**
- Now substituting the known values:
\[ \frac{\text{Weight of } Ag}{108} = \frac{8}{8} \]
- This simplifies to:
\[ \text{Weight of } Ag = 108 \text{ g} \]

### Final Answer:
The weight of silver displaced is **108 grams**.