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Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction `Cu(s)+2Ag^(+)(aq)rarrCu^(2+)(aq)+2Ag(s), E_(cell)^(@)=0.46 V`.

A

`4.0 xx 10^(10)`

B

`4.0 xx 10^(15)`

C

`2.4 xx 10^(10)`

D

`2.0 xx 10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
B
According to Nernst equation
`E_("cell")^(@) = (2.303 RT)/(nF) log K_(eq.)`
or `log K_(eq.) = (nFE_("cell")^(@))/(2.303 RT)`
`= ((2 mol)(96500 C mol^(-1))(0.46 V))/((2.303)(8.314 JK^(-1))(298 K))`
`= 15.56`
Thus
`K_(eq.) = 4.0 xx 10^(15)`
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