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The EMF of a cell is related to the equi...

The `EMF` of a cell is related to the equilitbrium constant of the cell reaction by

A

`E_("cell")^(@) = (RT)/(nF) ln K`

B

`E_("cell")^(@) = (2.303 RT)/(nF) log K`

C

'ln K = (nFE_("cell")^(@))/(RT)`

D

all of these

Text Solution

Verified by Experts

The correct Answer is:
D
Combining `Delta_(r)G^(@) = -nFE_("cell")^(@)` with the equation `Delta_("cell")G^(@) = -RT ln K`, gives
`nFE_("cell")^(@) = RT "in" K`
or `E_("cell")^(@) = (RT)/(nF) ln K`
`= (2.303 RT)/(nF) log K`
or `ln K = nFE_("cell")^(@)//RT`
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