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The resistance of an N//10 KCl solution ...

The resistance of an `N//10 KCl` solution is `245 ohms`. Calculate the equivalent conducatnce of the solution id the electrodes in the cell are `4 cm` apart and each having an area of `7.0` sq.cm.

A

`33.32 S cm^(2)`

B

`23.32 S cm^(2)`

C

`23.23 S cm^(2)`

D

`32.23 S cm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Equivalent conducatance `Lambda_(eq.)` = conducativity `(kappa)` `xx` Volume in `C C` containing `1` eq. of the substance
`R = 245`
`:. G = (1//245)S`
`K_("cell") = l//A = 4//7 cm^(-1)`
Conductivity `= G xx K_("cell") = ((1)/(245)S)((4)/(7)cm^(-1))`
`= 2.323 xx 10^(-3)S cm^(-1)`
`Lambda _(eq.) = kappa xx V`
`( 2.323 xx 10^(-3) S cm^(-1)) (10000 cm^(3))` [For `N//10` solution, `V = 10,000`]
`= 23.32 S cm^(2)`
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