A metal wire carries a current of `1` ampere. The number of electrons passing a given point in the wire in `1` second is

Options

A. `6.24 xx 10^(20)`
B. `6.24 xx 10^(16)`
C. `6.24 xx 10^(18)`
D. `6.24 xx 10^(14)`

Answer

C

Explanation

If we know the current in a circuit and the length of time it has been flowing, we can calculate the electric charge
Electric charge = electric current `xx` lapse
Corresponding units are
Coulomb = amperes `xx` seconds
The ampere `(A)` is the base unit of current in the international system `(SI)`. The coulomb `(C)`, the `SI` unit of electric charge, is equivalent to an ampere-second.
Here
Charge in coulomb = current in amperes `xx` time in seconds
`= 1 xx 1 = 1`
Recall, `96,500` coulomb corresponds to
`(6.022 xx 10^(23))/(96,500)` electrons
`6.24 xx 10^(18)` electrons