The density of `Cu` metal is `8.94 g` per ml. The charge in cou-lombs needed to plate an area `10 cm xx 10 cm` to a thickness of `10^(-2) cm` using `CuSO_(4)` solution as electrolyte is

Options

A. `27129.2` coulombs
B. `57612.5` coulombs
C. `11725.6` coulombs
D. `62117.5` coulombs

Answer

A

Explanation

Accoding to Faraday's laws
`(m)/(E) = (Q)/(F)`
Mass of copper to be deposited
= Volume deposited `xx` density of `Cu`
= Area `xx` Thickness `xx` density
`= (10 xx 10 cm^(2))(10^(-2)cm)(8.94 g cm^(-3))`
`= 8.94 g`
Electrode reaction :
`Cu^(2+)+2e^(-) rarr Cu`
Thus, equivalent mass of `Cu`
`= "Atomic mass"//2`
`= 63.5//2 = 31.8`