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The number of unpaired spins in the [Cr(...

The number of unpaired spins in the `[Cr(en)_(3)]^(2+)` ion is

A

two

B

four

C

three

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A

The magnetic properties of a complex ion depend on the number of unpaired electrons present. The actual number of unpaired electrons (or spins) in a complex ion can be found by magnetic measurments, and in general experimental findings supports predictions based on crystal field splitting. However a distinction between low and high spin complexes can be made only if the metal ion contains more than three and fewer than eight d electrons. The ground state electron configuration of `Cr^(2+)` is `[Ar]3d^(4)` . Since en is a strong field ligand, we expect `[Cr(en)_(3)]^(2+)` to be a low spin complex. According to crystal field orbital energy level diagram, all four electrons will be place in the lower d orbitals `(d_(xy), d_(yz)` and `d_(xz))` and there will be a total of two unpaired spins:
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Knowledge Check

  • The number of unpaired electrons in Cr^(3+) ion is

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