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The number of geometric isomers that can...

The number of geometric isomers that can exist for square planner complex ion `[Pt(CI)(PY)(NH_(3))(NH_(2)OH)]^(+)` is (Py = pyridine) :

A

3

B

4

C

6

D

2

Text Solution

Verified by Experts

The correct Answer is:
A

Three geometrical isomers are possible as shown below:
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