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CH(3)-CHCI-CH(2)=CH(3) has a chiral cent...

`CH_(3)-CHCI-CH_(2)=CH_(3)` has a chiral centre. Which one of the following represents its `R` configuration?

A

`CI-overset(C_(2)H_(5))overset(|)underset(H)underset(|)C-CH_(3)`

B

`H-overset(CH_(3))overset(|)underset(C_(2)H_(5))underset(|)C-CI`

C

`H_(3)C-overset(C_(2)H_(5))overset(|)underset(H)underset(|)C-CI`

D

`H-overset(C_(2)H_(5))overset(|)underset(CI)underset(|)C-CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
The priority order is `CI gtC_(2)H_(5) gtCH_(3) gt H`.

The `R` (for Laton word ''rectus'', meaning right) configuraiton is assigned to chiral carbon if the order of decreasing priority of the three higher ranking substituents is clockwise. The `S` (for Latin word ''sinister''n meaning left) configuration is assinged if the order of decreasing priority is anticlockwise.
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