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On acetylation with acetic anhydride, gl...

On acetylation with acetic anhydride, glucose gives

A

hexaacetate

B

pentaacetate

C

tetraacetate

D

triacetate

Text Solution

Verified by Experts

The correct Answer is:
B
Pentaacetate is formed as glucose contains `5 - OH` groups:
`HOCH_(2) (CHOH)_(4) (CHO) rarr Ac OCH_(2) (CHOAc)_(4) CHO`
`(Ac rarr CH_(3) CO-)`
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