The `H-O-H` bond angle in water is

The H-O-H bond angle in the water molecule is 105^@ , the H -O bond distance being 0.94 Å , The dipole moment for the moelcule is 1.85D . Calculate the charge on the oxygen atom .

The H-O-H bond angle in the water molecule is 105^@ , the H -O bond distance being 0.94 Å , The dipole moment for the moelcule is 1.85D . Calculate the charge on the oxygen atom .

Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R: Assertion A: The H-O-H bond angle in water molecule is 104.5^(@) Reason R: The lone pair - lone pair repulsion of electrons is higher than the bond pair - bond pair repulsion. In the light of the above statements, choose the correct answer from the options given below:

The dipole moment of water is 1.84D and dipole moment of O-H bond is 1.5D. Calculate the H-O-H bond angle in water.

Assertion: The C–O-C bond angle in ethers is higher than H-O-H bond angle in water. Reason Oxygen in both ethers and water is sp hybridized.

(A) The C-O-C bond angle in ethers is higher than H-O-H bond angle in water. (R ) Oxygen is sp^(3) - hybridized in both ethers and water.

C-O-C bond angle in ethers is higher than H-O-H bond angle in water through O is sp^3 -hybridisedin both the cases.