Pick out the correct statement with respect to `[Mn(CN)_(6)]^(3-)`:

Options

A. It is `sp^(3) d^(2)` hybridised and tetrahedral
B. It is `d^(2) sp^(3)` hybridised and octahedral
C. It is `dsp^(2)` hybridised and square planar
D. It is `sp^(3) d^(2)` hybridised and octahdral

Answer

B

Explanation

Oxid.no. of `Mn` in given complex is `+3`.
`Mn (3 d^(5) 4 s^(2)) implies Mn^(3+)(3 d^(4))`
Since `CN^(-)` is a strong field ligand, it reshuffle the configuration for `d^(2) sp^(2)` hybridization. The geometry corresponding to `C.N.` 6 is always octaheral