The geometry and magnetic behaviour of the complex `[Ni(CO)_4]` are

Options

A. square planar geometry and diamagnetic
B. tetraheral geometry and diamgnetic
C. square planer geometry and paramagnetic
D. tetrahedral geometry and paramagnetic

Answer

B

Explanation

`[Ni (CO)_(4)] implies Ni (0) implies 3 d^(8) 4 s^(2)`
Since `CO` is a strong field ligand, the resulting electronic configuration is:
It is diamagnetic due to absence of unpaired electrons. It gemetry is tetrahedral as `sp^(3)` hybrid obitals are involved in bonding.