In a head-on collision between an `alpha`-particle and a gold nucleus, the minimum distance of approach is `3.95 xx 10^(4)m`. Calculate the energy of the `alpha`-particle.

In a head on collision between an alpha particle and gold nucleus, the minimum distance of approach is 4xx10^(-14)m . Calculate the energy of of alpha -particle. Take Z=79 for gold.

In a head-on collision between and alpha -particle and a gold nucleus, the distance of closest approach is 4.13 fermi. Calculate the energy of the particle. (1 fermi = 10^(-15) m )

In a head on collision between an alpha particle and gold nucleus (Z=79), the distance of closest approach is 39.5 fermi. Calculate the energy of alpha -particle.

In a head on collision between an alpha particle and a gold nucleius (Z=79),the distnace of closet approach is 39.5 fermi.Calculate the enrgy of alpha particle.

The distance of closest approach of an alpha particle to the nucleus of gold is 2.73 xx 10^(-14) m. Calculate the energy of the alpha particle.

In Rutherford experiment, for head-on collision of alpha particles with a gold nucleus, the impact parameter is

An energetic a-particle experiences head-on collision with nucleus having Z = 85. If distance of closest approach is 1.85xx10^(-14)m then calculate energy of a particle.