[" 2.Let "f(x)=((256+ax)^(1/8)-2)/((32+bx)^(1/5)-2)*" If "f" is "],[" continuous at "x=0," then the value of "a/b" is "]

If f(x)=((256+ax)^((1)/(8))-2)/((32+bx)^((1)/(5))-2) is continuous at x=0 then the value of (a)/(b) is

If the function f(x)=((128 a+a x)^(1/8)-2)/((32+b x)^(1/5)-2) is continuous at x=0 , then the value of a/b is (A) 3/5f(0) (B) 2^(8/5)f(0) (C) (64)/5f(0) (D) none of these

If the function f(x)=((128 a+a x)^(1/8)-2)/((32+b x)^(1/5)-2) is continuous at x=0 , then the value of a/b is (A) 3/5f(0) (B) 2^(8/5)f(0) (C) (64)/5f(0) (D) none of these

If the function f(x)=((128 a+a x)^(1/8)-2)/((32+b x)^(1/5)-2) is continuous at x=0 , then the value of a/b is (A) 3/5f(0) (B) 2^(8/5)f(0) (C) (64)/5f(0) (D) none of these

If the function f(x)=((128a+ax)^((1)/(8))-2)/((32+bx)^((1)/(5))-2) is continuous at x=0, then the value of (a)/(b) is (A) (3)/(5)f(0)(B)2^((8)/(5))f(0)(C)(64)/(5)f(0)(D) none of these

Let f(x)=lim_( n to oo) (x^(2n-1) + ax^2 +bx)/(x^(2n) +1) . If f is continuous for x in R , then the value of a+8b is

Let f: R to R be a function defined as f(x)={(,(sin (a+1)x+sin 2x)/(2x), if x lt 0),(, b, if x=0), (,(sqrt(x+bx^(3))-sqrtx)/(bx^(5/2)), if x gt 0):} If f is continuous at x=0 then the value of a+b is equal to :

A function f is defined by f(x)= {{:((sin (a + 1) x + sinx)/(x)" if " x lt 0),(c " if " x = 0),(((x + bx^(2))^(1/2)- x^(1/2))/(bx^(3/2)) " if " x gt 0 ):} It f(x) is continuous at x = 0 , find the values of a,b and c .